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ID: 445
Viewed: 2946
Added: Aug 19, 2002
Version:
Snippet uploaded by: snippet
Written By: Unknown
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Replaces all occurances of sFindStr with sReplaceWithStr

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<!---Declaration--->
none

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<!---Code--->
Public Sub ReplaceAll(ByRef sOrigStr As String,  _
ByVal sFindStr As String, _
ByVal sReplaceWithStr As String, _
Optional bWholeWordsOnly As Boolean)
Dim lPos As Long
Dim lPos2 As Long
Dim sTmpStr As String
Dim bReplaceIt As Boolean
Dim lFindStr As Long


On Error GoTo vbErrorHandler

lFindStr = Len(sFindStr)

lPos2 = 1
bReplaceIt = True
sTmpStr = sOrigStr

Do
lPos = InStr(lPos2, sOrigStr, sFindStr)
If lPos = 0 Then
Exit Do
End If
If bWholeWordsOnly Then
On Error Resume Next
If lPos = 1 Or (Mid$(sOrigStr, lPos - 1, 1) = " ") Then
If (Mid$(sOrigStr, lPos + lFindStr, 1) = " ") Or Mid$(sOrigStr, lPos + lFindStr + 1, 1) = "" Then
bReplaceIt = True
Else
bReplaceIt = False
End If
End If
End If
If bReplaceIt Then
If lPos > 1 Then
sTmpStr = Left$(sOrigStr, lPos - 1)
Else
sTmpStr = ""
End If
sTmpStr = sTmpStr & sReplaceWithStr
sTmpStr = sTmpStr & Mid$(sOrigStr, lPos + lFindStr, Len(sOrigStr) - (lPos + lFindStr - 1))
sOrigStr = sTmpStr
End If
lPos2 = lPos + 1
Loop
sOrigStr = sTmpStr
Exit Sub

vbErrorHandler:
Err.Raise Err.Number, "StrHandler ReplaceAll", Err.Description


End Sub;


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